WebIn figure, ABCD is a trapezium of area 24.5 sq. cm. In it, AD BC, ∠ DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region 2. In figure, ABDC is a quadrant of a circle of radius 28 cm and a semicircle BEC is drawn with BC as diameter. Find B the area of the shaded region. 3. WebAug 24, 2024 · asked Aug 24, 2024 in Mathematics by AbhinavMehra (22.6k points) In figure, ABCD is a trapezium with AB DC. AB = 18 cm, DC = 32 cm and distance between …
In the given figure, ABCD is a trapezium of area 24.5 cm 2 . If AD ...
WebArea of trapezium = 24.5 cm 2 Area of trapezium = a + b 2 h e i g h t [ = A D + B C 2 A B 24.5 = 10 + 4 2 A B 24.5 7 = A B AB = 3.5 cm Thus, radius = 3.5 cm Area of quadrant = Area of …WebFind the area enclosed between two concentric circles of radii 3.5 cm and 7 cm. A third concentric circle is drawn outside the 7 cm circle , such that the area enclosed between it and the 7 cm circle is same as that between the two inner circles . Find the radius of the third circle correct to one decimal place.roll top bed
In figure 3, ABCD is a trapezium of area 24.5 sq. cm. In it, AD BC ...
WebApr 30, 2024 · It is given that the area of trapezium ABCD is 24.5 cm^2 . And AD BC WebApr 12, 2024 · Here, two parallel sides of trapezium are AD and BC. and distance between them is 14 m. ∴ Area of trapezium = 1/2 (1·5 + 8) × 14. = 1/2 × 9·5 × 14 = 66 × 5 m 2. Question 3. The area of a trapezium is 360 m2, the distance between two parallel sides is 20 m and one of the parallel side is 25 m. Find the other parallel side.WebABCDis a trapezium of area 24.5sq. cm. In it, AD∥BC,∠DAB=90∘,AD=10 cm and BC=4 cm. If ABEis a quadrant of a circle, find the area of the shaded region. [Take π=722 ]. Hard Open in App Solution Verified by Toppr Given: AD=10cm BC=4cm Area of trapezium =24.5 cm2 Area of trapezium =2a+b ×height 24.5=2AD+BC ×AB 24.5=210+4 ×AB AB=3.5cm Radius =3.5cmroll top beer cooler